Nitrobenzene reduction is one of the most important topics in the Class 12 Chemistry syllabus, especially within the chapter on amines. It plays a crucial role in understanding reaction mechanisms, product formation, and industrial applications. A highly effective way to master this topic is by practicing Nitrobenzene Reduction MCQs Class 12 with Answers, which helps apirants strengthen both conceptual clarity and exam readiness.

The reduction of nitrobenzene can lead to different products depending on the reaction conditions and reagents used. For instance, reduction in acidic medium using reagents like tin and hydrochloric acid produces aniline, while reduction in neutral or alkaline conditions may yield different intermediates such as phenylhydroxylamine or azobenzene. By working through Nitrobenzene Reduction MCQs Class 12 with Answers, aspirants can clearly understand how varying conditions affect the outcome of the reaction.

One of the key learning aspects of this topic is identifying the correct reagent for a desired product. For example, catalytic hydrogenation with hydrogen gas in the presence of nickel or palladium leads to complete reduction forming aniline. Practicing Nitrobenzene Reduction MCQs Class 12 with Answers enables aspirants to recognize such reagent-specific transformations quickly during exams.

Another important concept covered through Nitrobenzene Reduction MCQs Class 12 with Answers is the formation of intermediate compounds like nitrosobenzene, azobenzene, and hydrazobenzene. These intermediates are often part of stepwise reduction pathways and are frequently tested in competitive exams. Regular exposure to Nitrobenzene Reduction MCQs Class 12 with Answers helps students understand these sequences and avoid confusion.

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Nitrobenzene Reduction MCQs Class 12 with Answers:

1. When p-nitrobromobenzene reacts with sodium ethoxide, the product obtained is:

a) p-nitroanisole
b) ethyl phenyl ether
c) p-nitrophenetole
d) no reaction
Answer: c

2. Nitrobenzene + Br₂/Fe³⁺ gives:

a) m-bromonitrobenzene
b) o-bromonitrobenzene
c) p-bromonitrobenzene
d) o & p mixture
Answer: a

3. Compound with smell of bitter almonds:

a) aniline
b) phenyl isocyanide
c) benzonitrile
d) nitrobenzene
Answer: d

4. Tertiary amine is less basic due to:

a) inductive effect
b) peroxide effect
c) steric effect
d) resonance
Answer: c

5. Blue colour with nitrous acid is given by:

a) 2-methyl-2-nitropropane
b) 2-methyl-1-nitropropane
c) 2-nitropropane
d) nitrobenzene
Answer: c

6. Nitration of nitrobenzene gives:

a) meta-dinitrobenzene
b) ortho-dinitrobenzene
c) para-dinitrobenzene
d) trinitrobenzene
Answer: a

7. Stability order of carbanions:

a) I > II > III
b) I > III > II
c) II > I > III
d) II > III > I
Answer: b

8. Nitrobenzene + Zn/alcoholic KOH gives:

a) aniline
b) hydrazobenzene
c) azobenzene
d) benzamide
Answer: b

9. Nitro group in benzene ring:

a) activates EAS
b) deactivates EAS
c) activates NAS
d) makes ring basic
Answer: b

10. Decreasing activation of aniline ring by:

a) dil. HCl
b) ethanol
c) acetic acid
d) acetyl chloride
Answer: d

11. Raw material for phthalic acid manufacture:

a) benzene
b) salicylic acid
c) anthranilic acid
d) naphthalene
Answer: d

12. Reaction producing aniline:

a) C₆H₅NO₂ + Zn/HCl
b) Zn/NH₄Cl
c) LiAlH₄
d) KOH
Answer: a

13. Product of carbylamine reaction:

a) C₆H₅NH₂
b) COCl₂
c) C₆H₅CN
d) C₆H₅NC
Answer: d

14. Statement-based question on aliphatic amines with nitrous acid

Statement I: Primary aliphatic amines react with HNO₂ to give unstable diazonium salts.
Statement II: Primary aliphatic amines react with HNO₂ to form diazonium salts which are stable even above 300 K.

a) Statement I is incorrect but Statement II is correct
b) Both Statement I and Statement II are correct
c) Both Statement I and Statement II are incorrect
d) Statement I is correct but Statement II is incorrect

Answer: d

15.Which compound forms an orange azo dye with phenol after diazotization?
a) Benzene
b) Aniline
c) Nitrobenzene
d) Toluene
Answer: b

16.Which reagent generates nitrous acid in situ for diazotization?
a) NaNO₂ + HCl
b) NaCl + HNO₃
c) NH₄Cl + NaOH
d) HNO₃ alone
Answer: a

17. Hydrolysis giving phenol:

a) cumene
b) benzenediazonium chloride
c) benzal chloride
d) ketal
Answer: b

18.

Aromatic diazonium salts are stable at:
a) 373 K
b) 298 K
c) 273–278 K
d) 0 K
Answer: c

19. Product A in reaction:

a) phenol
b) benzene diazonium salt
c) benzene
d) nitrobenzene
Answer: b

20. Reagent for bromobenzene formation:

a) HBr
b) MgBr₂
c) Cu₂Br₂/HBr
d) KBr
Answer: c

21. X and Y in reactions:

a) NaNO₂, Cl₂
b) NaNO₂/HCl, HCl
c) NaNO₂/HCl, Cu/HCl
d) NaNH₂
Answer: c

22. Most stable diazonium salt:

a) C₆H₅CH₂N₂⁺
b) C₆H₅N₂⁺
c) CH₃CH₂N₂⁺
d) substituted
Answer: b

23. Reduction of nitrobenzene gives:

a) hydrazobenzene
b) azobenzene
c) aniline
d) hydroxylamine
Answer: a

24. Role of nitrous acid in diazotization:

a) prevents hydrolysis
b) gives NO⁺
c) neutralizes base
d) all
Answer: b

25. Nitrobenzene → azobenzene reagent:

a) Zn/NH₄Cl
b) Zn/NaOH, CH₃OH
c) Zn/NaOH
d) LiAlH₄
Answer: b

26. Which will not undergo diazotization?

a) C₆H₅NH₂
b) C₆H₅CH₂NH₂
c) none
d) all
Answer: b

27.Azo coupling reaction occurs mainly with:
a) Alkanes
b) Activated aromatic rings
c) Alkynes
d) Alcohols
Answer: b

28. Fluorobenzene preparation:

a) phenol + HF
b) diazotisation + HBF₄
c) F₂ gas
d) NaF
Answer: b

29.Benzene diazonium chloride reacts with aniline to form:
a) Benzene
b) Phenol
c) Azo compound
d) Nitrobenzene
Answer: c

30. Assertion-Reason (nitration of aniline):

a) both true, correct explanation
b) both true, not explanation
c) A true, R false
d) A false, R true
Answer: a