• iamal
• February 13, 2026

Crack Kohlrausch Law Based MCQs Electrochemistry: Ultimate Success Blueprint for Top Scores

Kohlrausch law based mcqs electrochemistry is one of the most important focus areas for students preparing for board exams and competitive entrance tests. The concept behind Kohlrausch law based mcqs electrochemistry revolves around the independent migration of ions at infinite dilution. According to Kohlrausch’s law, at infinite dilution, each ion contributes independently to the total molar conductivity of the electrolyte. This principle becomes extremely useful when solving Kohlrausch law based mcqs electrochemistry that involve weak electrolytes, limiting molar conductivity, and ionic contributions.

When aspirants practice Kohlrausch law based mcqs electrochemistry, they must clearly understand that molar conductivity at infinite dilution can be expressed as the sum of the limiting ionic conductivities of the cation and anion. This additive property allows us to calculate the limiting molar conductivity of weak electrolytes indirectly. Many numerical problems in Kohlrausch law based mcqs electrochemistry test this exact concept by giving values of strong electrolytes and asking for unknown weak electrolyte conductivities.

Another major application frequently tested in Kohlrausch law based mcqs electrochemistry is the determination of degree of dissociation and dissociation constant of weak acids or bases. Since weak electrolytes do not completely ionize, their molar conductivity increases sharply on dilution. Using the limiting molar conductivity obtained through Kohlrausch’s law, aspirants can calculate the degree of dissociation. Therefore, a strong conceptual grip is essential for solving Kohlrausch law based mcqs electrochemistry accurately.

In competitive examinations, Kohlrausch law based mcqs electrochemistry often include mixed conceptual and numerical questions. Aspirants may be given Λm° values of strong electrolytes like NaCl, HCl, or NaOH and asked to compute Λm° of weak electrolytes such as CH₃COOH or NH₄OH. This type of reasoning-based problem is very common in Kohlrausch law based mcqs electrochemistry because it checks whether the aspirant understands ionic independence and conductivity relationships.

Another frequently tested area in Kohlrausch law based mcqs electrochemistry is the relationship between conductivity, molar conductivity, and concentration. As concentration decreases, molar conductivity increases due to decreased interionic interactions. Strong electrolytes show a linear decrease of molar conductivity with √C, while weak electrolytes show a nonlinear curve. Conceptual clarity in these trends helps in solving assertion-reason type Kohlrausch law based mcqs electrochemistry.

Aspirants should also remember that Kohlrausch’s law applies strictly at infinite dilution. Many tricky Kohlrausch law based mcqs electrochemistry test whether the aspirant incorrectly applies the law at finite concentrations. At higher concentrations, ion-ion interactions become significant, and deviations occur. Recognizing these limitations is crucial for avoiding conceptual errors in Kohlrausch law based mcqs electrochemistry.

In addition, Kohlrausch law based mcqs electrochemistry may test the derivation of ionic conductivities using transport numbers and limiting molar conductivity data. Transport numbers indicate the fraction of total current carried by each ion, and when combined with limiting molar conductivity, they help determine individual ionic conductivities. This integration of concepts frequently appears in higher-level Kohlrausch law based mcqs electrochemistry.

Another important application covered in Kohlrausch law based mcqs electrochemistry is the calculation of solubility of sparingly soluble salts. By measuring the conductivity of a saturated solution and applying Kohlrausch’s law, one can determine solubility and even calculate the solubility product constant (Ksp). Such application-based questions are very popular in advanced Kohlrausch law based mcqs electrochemistry.

Conceptual mastery is more important than memorization while preparing for Kohlrausch law based mcqs electrochemistry. Aspirants should practice deriving expressions step by step, understanding unit conversions, and carefully analyzing given data. Attention to units such as S cm² mol⁻¹ and correct usage of concentration values prevents calculation mistakes in Kohlrausch law based mcqs electrochemistry.

Kohlrausch Law Based MCQs Electrochemistry:

1. The molar conductivity of a 0.5 mol/cm³ solution of AgNO₃ with electrolytic conductivity of 5.76 × 10⁻³ S cm⁻¹ at 298 K is
A) 28.8 S cm² mol⁻¹
B) 11.52 S cm² mol⁻¹
C) 0.086 S cm² mol⁻¹
D) 2.88 S cm² mol⁻¹
Answer: B

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2. The order of equivalent conductances at infinite dilution for LiCl, NaCl and KCl is
A) LiCl > NaCl > KCl
B) KCl > NaCl > LiCl
C) NaCl > KCl > LiCl
D) KCl > LiCl > NaCl
Answer: B

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3. Consider the following statements:
Statement I: The conductance depends on the number of ions and ion mobility. The equivalent conductance increases with increase in dilution, the specific conductance diminishes.
Statement II: The total number of ions increases on account of increased ionization due to dilution, but the number of ions per unit volume decreases.
A) Both statements are true and statement II is the correct explanation of statement I
B) Both statements are true but statement II is not the correct explanation of statement I
C) Statement I is true, but statement II is false
D) Statement II is true, but statement I is false
Answer: A

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4. The value of electrical resistance at super conductivity is
A) Low
B) High
C) Zero
D) Infinite
Answer: C

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5. Pure silicon doped with phosphorus is:
A) Amorphous
B) p-type semiconductor
C) n-type semiconductor
D) Insulator
Answer: C

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6. Silicon doped with arsenic is:
A) p-type semiconductor
B) n-type semiconductor
C) Intrinsic semiconductor
D) Insulator
Answer: B

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7. The conductivity of 0.001028 mol L⁻¹ acetic acid is 4.95 × 10⁻⁵ S cm⁻¹. Find its dissociation constant if Λm for acetic acid is 390.5 S cm² mol⁻¹
A) 2.18 × 10⁻⁵ mol L⁻¹
B) 1.78 × 10⁻⁵ mol L⁻¹
C) 3.72 × 10⁻⁴ mol L⁻¹
D) 2.37 × 10⁻⁴ mol L⁻¹
Answer: B

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8. At a particular temperature, the ratio of equivalent conductance to specific conductance of a 0.01 N NaCl solution is
A) 10⁶ cm³
B) 10⁸ cm³
C) 10⁵ cm²
D) 10⁵ cm³
Answer: D

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9. The equivalent conductivity of a solution containing 2.54 g of CuSO₄ per L is 91.0 Ω⁻¹ cm² eq⁻¹. Its conductivity would be
A) 2.9 × 10⁻³ Ω⁻¹ cm⁻¹
B) 1.8 × 10⁻² Ω⁻¹ cm⁻¹
C) 2.9 × 10⁻² Ω⁻¹ cm⁻¹
D) 1.8 × 10⁻³ Ω⁻¹ cm⁻¹
Answer: A

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10. Equivalent conductances of Ag⁺ and NO₃⁻ at infinite dilution are respectively
A) 195.2, 133.3
B) 61.9, 71.4
C) 71.4, 61.9
D) 63.3, 70.0
Answer: B

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11. Equivalent conductance at infinite dilution of Al₂(SO₄)₃ is
A) 2ΛAl³⁺° + 3ΛSO₄²⁻°
B) ΛAl³⁺° + ΛSO₄²⁻°
C) (ΛAl³⁺° + 3ΛSO₄²⁻°) × 6
D) ⅓ΛAl³⁺° + ½ΛSO₄²⁻°
Answer: B

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12. Equivalent conductance at infinite dilution of HF
A) By extrapolation of HCl, HBr, HI
B) By direct measurement
C) From NaF, NaCl, HCl
D) Undefined
Answer: C

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13. Molar conductivity of NaNO₃ is
A) 138 S cm² mol⁻¹
B) 87 S cm² mol⁻¹
C) 130 S cm² mol⁻¹
D) -140 S cm² mol⁻¹
Answer: B

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14. Molar conductivity of CaCl₂ at infinite dilution is
A) 118.8 × 10⁻⁴
B) 154.6 × 10⁻⁴
C) 273.54 × 10⁻⁴
D) 196.2 × 10⁻⁴
Answer: C

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15. For strong electrolytes the plot of molar conductance vs √C is
A) Parabolic
B) Linear
C) Sinusoidal
D) Circular
Answer: B

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16. Charge carriers in p-type semiconductors are
A) Electrons
B) Protons
C) Neutrons
D) Positive holes
Answer: D

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17. Electrical conductivity of metal decreases with increase of temperature due to
A) Enhanced vibration of metal ions
B) Movement of electrons
C) Chemical energy
D) Increase of thermal energy
Answer: A

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